jika fungsi f(x) = 1 - 4 kuadrat g(x) = akar x + 1 / x dan f bundaran g bundaram h inver = akar 2x. rumus h(x)
4. ( f o g o h )⁻¹(x) = √2x
(x)² = (√2y )²
x² = 2y
½x² = y
( f o g o h )(x) = ½x²
( f o g o h )(x) = f o g[ h(x) ]
[tex] \frac{x {}^{2} }{2} = f( \sqrt{ \frac{h(x) + 1}{h(x)} } ) \\ \frac{x {}^{2} }{2} = 1 - 4( \sqrt{ \frac{h(x) + 1}{h(x)} } ) {}^{2} \\ \frac{x {}^{2} }{2} = 1 - 4( \frac{h(x) + 1}{h(x)} ) \\ \frac{x {}^{2} }{2} = \frac{h(x) - 4(h(x) + 1)}{h(x)} \\ \frac{x {}^{2} }{2} = \frac{h(x) - 4h(x) - 4}{h(x)} \\ \frac{x {}^{2} }{2} = \frac{ - 3h(x) - 4}{h(x)} [/tex]
x² h(x) = 2( -3h(x) - 4 )
x² h(x) = -6h(x) - 8
x² h(x) + 6h(x) = -8
h(x) [ x² + 6 ] = -8
[tex]h(x) = \frac{ - 8}{x {}^{2} + 6 } [/tex]
[answer.2.content]
